Question

fill in the blank 25 points given △jkl with points j(1, -2), k(4, -1), and l(3, -3), graph it, and its reflection in over each line. then fill in the points for △jkl in the space provided. dado △jkl con los puntos j(1, -2), k(4, -1) y l(3, -3), graficarlo, y su reflejo en cada linea. a continuación, rellene los puntos para △jkl en el espacio proporcionado. reflection line (linea de reflexión:); x-axis (eje x) answer: j ( type your answer... type your answer... ) k ( type your answer... type your answer... ) l ( type your answer... type your answer... )

Explanation:

Step1: Recall reflection over x - axis rule

The rule for reflecting a point \((x,y)\) over the \(x\) - axis is \((x,-y)\). That is, we keep the \(x\) - coordinate the same and change the sign of the \(y\) - coordinate.

Step2: Find \(J'\)

For point \(J(1,-2)\), using the reflection rule over the \(x\) - axis:
The \(x\) - coordinate remains \(1\), and the \(y\) - coordinate becomes \(-(-2)=2\). So \(J'(1,2)\).

Step3: Find \(K'\)

For point \(K(4,-1)\), using the reflection rule over the \(x\) - axis:
The \(x\) - coordinate remains \(4\), and the \(y\) - coordinate becomes \(-(-1) = 1\). So \(K'(4,1)\).

Step4: Find \(L'\)

For point \(L(3,-3)\), using the reflection rule over the \(x\) - axis:
The \(x\) - coordinate remains \(3\), and the \(y\) - coordinate becomes \(-(-3)=3\). So \(L'(3,3)\).

Answer:

\(J'(1,2)\)
\(K'(4,1)\)
\(L'(3,3)\)