Question

find the measure of ∠eod.
m∠eod = 65 × °.
classify ∠eod.
∠eod is a(n) angle.

Explanation:

Step1: Identify the angles from the protractor

From the protractor, the angle for ray OE is 40° (from the right - hand scale, since OB is along the 0° - 180° line) and the angle for ray OD is 110°? Wait, no, let's look at the scales. Wait, the inner and outer scales. Let's check the positions. The ray OE: looking at the protractor, if we take the outer scale (or the inner scale), let's see the markings. Wait, the ray OD: let's see the angle of OD with respect to OB. Wait, maybe better to take the difference. Let's see, the angle of OE: from the 0° (OB) to OE, let's check the scale. The OE is at 40° (if we take the lower scale, the one where B is at 0°). The OD is at 110°? Wait, no, maybe I got the scales wrong. Wait, the protractor has two scales: one going from 0° to 180° clockwise (outer) and one counter - clockwise (inner). Let's see the positions of the rays. The ray OE: let's see the mark, E is at 40° (if we consider the scale where B is 0° and A is 180°). The ray OD: let's see, D is at 110°? Wait, no, the angle between OD and OE is the difference between their measures from the same scale. Wait, let's take the scale where OB is 0° (right side, 0°) and OA is 180° (left side). Then, the measure of ∠EOB is 40° (since E is at 40° on the 0° - 180° scale from B) and the measure of ∠DOB is 110°? No, that can't be. Wait, maybe the other way. Wait, the ray OD: let's check the angle from OE to OD. Wait, looking at the protractor, the OE is at 40° (from OB) and OD is at 110°? No, wait, the correct way is to find the measure of ∠EOD by subtracting the two angles. Let's see, the angle of OE with respect to OB is 40° (using the outer scale, where B is 0° and A is 180°), and the angle of OD with respect to OB is 110°? No, that would make ∠EOD = 110° - 40° = 70°? Wait, no, maybe I misread the protractor. Wait, let's look at the numbers. The OE is at 40° (the mark near E is at 40°) and OD is at 110°? Wait, the numbers on the protractor: the inner scale (the one closer to the center) for OD: let's see, the inner scale has 120, 110, 100... Wait, maybe the outer scale: the outer scale for OE is 40° (since from B (0°) moving counter - clockwise, OE is at 40°), and OD is at 110°? No, that would be 110 - 40 = 70. Wait, maybe the correct difference is 110 - 40 = 70? Wait, let's re - examine. The protractor: the ray OE is at 40° (from the 0° line OB) and ray OD is at 110° (from OB). So the measure of ∠EOD is 110°−40° = 70°.

Step2: Calculate the angle

To find \( m\angle EOD \), we subtract the measure of \( \angle EOB \) from the measure of \( \angle DOB \). Let \( m\angle EOB = 40^{\circ} \) and \( m\angle DOB=110^{\circ} \). Then \( m\angle EOD=m\angle DOB - m\angle EOB \).
\( m\angle EOD = 110^{\circ}-40^{\circ}=70^{\circ} \)

Answer:

\( 70^{\circ} \)