Question

graph the compound inequality. x < -3 or x > -2 plot the endpoints. select an endpoint to change it from closed to open. select the middle of a segment, ray, or line to delete it. number line with -4, -3, -2, -1, 0, 1, 2, 3 submit

Explanation:

Step1: Analyze \( x < -3 \)

For the inequality \( x < -3 \), we draw an open circle at \( -3 \) (since \( x \) is not equal to \( -3 \)) and draw a ray pointing to the left (towards negative infinity) from \( -3 \).

Step2: Analyze \( x > -2 \)

For the inequality \( x > -2 \), we draw an open circle at \( -2 \) (since \( x \) is not equal to \( -2 \)) and draw a ray pointing to the right (towards positive infinity) from \( -2 \).

Graph Description:

• At \( x = -3 \): Open circle, ray to the left (covers \( \dots, -5, -4, -3.1, -3.01, \dots \)).
• At \( x = -2 \): Open circle, ray to the right (covers \( -1.99, -1.9, 0, 1, 2, \dots \)).

(Note: Since this is a graphing task, the final answer is the graphical representation as described above. If we were to describe the intervals, the solution is \( (-\infty, -3) \cup (-2, \infty) \))

Answer:

The graph has an open circle at \( -3 \) with a ray to the left and an open circle at \( -2 \) with a ray to the right. The solution in interval notation is \( (-\infty, -3) \cup (-2, \infty) \)