Question

perform the indicated operation. (simplify your answer completely.)
$(x - 6)(x + 2) + (2x - 1)(x - 4)$

Explanation:

Step1: Expand first product

$(x-6)(x+2) = x^2 + 2x - 6x - 12 = x^2 - 4x - 12$

Step2: Expand second product

$(2x-1)(x-4) = 2x^2 - 8x - x + 4 = 2x^2 - 9x + 4$

Step3: Add the two expansions

$(x^2 - 4x - 12) + (2x^2 - 9x + 4)$

Step4: Combine like terms

$x^2 + 2x^2 - 4x - 9x - 12 + 4 = 3x^2 - 13x - 8$

Answer:

$3x^2 - 13x - 8$