Question

prove: the sum of two multiples of 3 is a multiple of 3. 3m + 3n = ?(m + n) = a multiple of

Explanation:

Step1: Factor out common term

$3m + 3n = 3(m + n)$

Step2: Verify multiple property

Since $m+n$ is an integer, $3(m+n)$ is a multiple of 3.

Answer:

The missing value in the first box is $3$, and the missing value in the second box is $3$. The complete proof confirms that the sum of two multiples of 3 is a multiple of 3.