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Question
question
express in simplest radical form.
$sqrt{9}$
answer attempt 2 out of 2
$3sqrt{3}$
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Step1: Recall square - root property
We know that if \(a^2 = b\), then \(\sqrt{b}=a\) (for \(a\geq0\)). Since \(3\times3 = 9\), \(\sqrt{9}=\sqrt{3^2}\).
Step2: Simplify the square - root
By the property \(\sqrt{a^2}=a\) (\(a\geq0\)), when \(a = 3\), \(\sqrt{9}=3\).
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