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Question
section 2 - 1b: slope - intercept form graph the linear equation in slope - intercept form. 5) $y=\frac{4}{5}x - 1$ $m = \frac{4}{5}$, $b=(-1)$ $(0,-1)$ 6) $y=-3x + 6$ $m=-3$, $b = 6$ $(0,6)$
Step1: Identify slope and y - intercept for \(y=\frac{4}{5}x - 1\)
The slope \(m=\frac{4}{5}\) and y - intercept \(b=- 1\). Plot the y - intercept point \((0,-1)\) on the coordinate plane.
Step2: Use the slope to find another point
The slope \(\frac{4}{5}\) means for every 5 units we move to the right along the x - axis, we move 4 units up along the y - axis. Starting from \((0,-1)\), moving 5 units right to \(x = 5\) and 4 units up gives the point \((5,3)\). Draw a line through \((0,-1)\) and \((5,3)\).
Step3: Identify slope and y - intercept for \(y=-3x + 6\)
The slope \(m=-3=-\frac{3}{1}\) and y - intercept \(b = 6\). Plot the y - intercept point \((0,6)\) on the coordinate plane.
Step4: Use the slope to find another point
The slope \(-3\) means for every 1 unit we move to the right along the x - axis, we move 3 units down along the y - axis. Starting from \((0,6)\), moving 1 unit right to \(x = 1\) and 3 units down gives the point \((1,3)\). Draw a line through \((0,6)\) and \((1,3)\).
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The graph of \(y=\frac{4}{5}x - 1\) has a line passing through \((0,-1)\) and \((5,3)\); the graph of \(y=-3x + 6\) has a line passing through \((0,6)\) and \((1,3)\) (the actual graphing is done on the provided grid paper).