QUESTION IMAGE
Question
solve each equation for the designated variable.
- solve for m:
y = mx + 5
- solve for b:
p = 2a + 3b + c
- solve for c:
r=\frac{c + d}{2}
- solve for s:
a=\frac{pi r^{2}cdot s}{360}
- solve for y:
ax + by = c
- solve for b:
x = 2(a + 2b + 3c)
Step1: Isolate mx term
Subtract 5 from both sides of $y = mx+5$.
$y - 5=mx$
Step2: Solve for m
Divide both sides by x (assuming $x
eq0$).
$m=\frac{y - 5}{x}$
Step3: For $P = 2a+3b + c$, isolate 3b term
Subtract 2a and c from both sides.
$3b=P - 2a - c$
Step4: Solve for b
Divide both sides by 3.
$b=\frac{P - 2a - c}{3}$
Step5: For $R=\frac{c + d}{2}$, isolate c + d term
Multiply both sides by 2.
$2R=c + d$
Step6: Solve for c
Subtract d from both sides.
$c=2R - d$
Step7: For $A=\frac{\pi r^{2}\cdot S}{360}$, isolate $\pi r^{2}\cdot S$ term
Multiply both sides by 360.
$360A=\pi r^{2}\cdot S$
Step8: Solve for S
Divide both sides by $\pi r^{2}$ (assuming $\pi r^{2}
eq0$).
$S=\frac{360A}{\pi r^{2}}$
Step9: For $Ax+By = C$, isolate By term
Subtract Ax from both sides.
$By=C - Ax$
Step10: Solve for y
Divide both sides by B (assuming $B
eq0$).
$y=\frac{C - Ax}{B}$
Step11: For $x = 2(a + 2b+3c)$, first expand the right - hand side
$x = 2a+4b + 6c$
Step12: Isolate 4b term
Subtract 2a and 6c from both sides.
$4b=x - 2a - 6c$
Step13: Solve for b
Divide both sides by 4.
$b=\frac{x - 2a - 6c}{4}$
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- $m=\frac{y - 5}{x}$
- $b=\frac{P - 2a - c}{3}$
- $c=2R - d$
- $S=\frac{360A}{\pi r^{2}}$
- $y=\frac{C - Ax}{B}$
- $b=\frac{x - 2a - 6c}{4}$