Question

1. what is the shortcoming of the classical solar system model model? (1 pt)

a. too many are photons emitted in the visible region of the emission spectrum.
b. too many photons are emitted in the uv region.
c. the atom is not stable. the electron loses energy, spirals into the nucleus and the atom is destroyed. in this model atoms should not exist.
energy wavelength and frequency calculations:

1. complete these calculations and enter the numerical answers (without units) into the report on d2l.

a. if a photon of monochromatic light has a wavelength of 94 nm, what is its frequency (expressed in units of s⁻¹ or hz)? (1 pt)
b. what is the energy of this photon (in joules)? (1 pt)

Explanation:

Step1: Recall the speed - wavelength - frequency relation

The speed of light $c = \lambda
u$, where $c = 3\times10^{8}\ m/s$, $\lambda$ is the wavelength and $
u$ is the frequency. First, convert the wavelength from nm to m. Given $\lambda=94\ nm = 94\times10^{- 9}\ m$. Then, $
u=\frac{c}{\lambda}$.
$
u=\frac{3\times10^{8}}{94\times10^{-9}}\ Hz\approx3.19\times10^{15}\ Hz$

Step2: Recall the energy - frequency relation

The energy of a photon is given by $E = h
u$, where $h = 6.63\times10^{-34}\ J\cdot s$ and $
u$ is the frequency calculated above.
$E=(6.63\times10^{-34})\times(3.19\times10^{15})\ J\approx2.11\times10^{-18}\ J$

Step3: Answer question 9

The classical solar - system model of the atom (Rutherford's model) has the problem that the electron, which is accelerating as it moves in a circular path around the nucleus, should lose energy by emitting electromagnetic radiation, spiral into the nucleus and the atom should be destroyed. In reality, atoms are stable.

Answer:

1. c. The atom is not stable. The electron loses energy, spirals into the nucleus and the atom is destroyed. In this model atoms should not exist.
2. a. $3.19\times10^{15}$
3. b. $2.11\times10^{-18}$