Question

work each of the following problems. show all work. 5. a ladybug walks 10 cm forward then 5 cm backward in 20 seconds. what is the average speed of the ladybug?

Explanation:

Step1: Calculate total distance

The ladybug walks 10 cm forward and 5 cm backward. Total distance is the sum of these distances: $10 + 5 = 15$ cm.

Step2: Use average speed formula

Average speed $v = \frac{\text{total distance}}{\text{total time}}$. Total time is 20 seconds. So $v = \frac{15}{20} = 0.75$ cm/s.

Answer:

The average speed of the ladybug is $0.75$ cm/s.