Question

you have a graduated cylinder, which is filled with water up to 150 ml mark. you add a hunk of iron, and the water level rises to 425 ml. what is the mass of the iron? (the density if iron is 7.87 g/cm^3)
425
150
275
7.87
2160

Explanation:

Step1: Find volume of iron

Volume of iron = Final volume - Initial volume = \( 425 \, \text{mL} - 150 \, \text{mL} = 275 \, \text{mL} \). Since \( 1 \, \text{mL} = 1 \, \text{cm}^3 \), volume \( V = 275 \, \text{cm}^3 \).

Step2: Use density formula to find mass

Density formula: \(
ho = \frac{m}{V} \), so \( m =
ho \times V \). Substitute \(
ho = 7.87 \, \text{g/cm}^3 \) and \( V = 275 \, \text{cm}^3 \): \( m = 7.87 \times 275 = 2164.25 \approx 2160 \, \text{g} \) (rounded).

Answer:

2160