Question

if you push a crate horizontally with 100 n across a 10-m factory floor and friction between the crate and the floor is a steady 70 n, how much kinetic energy is gained by the crate?
300 j
700 j
1000 j
400 j
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Explanation:

Step1: Find net force

Net force \( F_{net} = F_{applied} - F_{friction} \)
\( F_{applied} = 100\ N \), \( F_{friction} = 70\ N \)
\( F_{net} = 100 - 70 = 30\ N \)

Step2: Calculate work done (kinetic energy gain)

Work \( W = F_{net} \times d \), distance \( d = 10\ m \)
\( W = 30 \times 10 = 300\ J \)

Answer:

300 J (assuming the first option is 300 J, as the text in the option seems to have a typo like "300 3" but likely intended 300 J)