Question

1. classify the equation 6(x + 2) = 5(x + 7) as having one solution, no solution, or infinitely many solutions.

Explanation:

Step1: Expand both sides

$6(x + 2)=6x+12$ and $5(x + 7)=5x + 35$, so the equation becomes $6x+12 = 5x+35$.

Step2: Isolate the variable

Subtract $5x$ from both sides: $6x - 5x+12=5x - 5x+35$, which simplifies to $x+12 = 35$.

Step3: Solve for x

Subtract 12 from both sides: $x+12-12=35 - 12$, getting $x = 23$.

Answer:

one solution