Question

(-3, -7) and (-7, -1) click twice to draw a line. click a segment to erase it. leg 1: leg 2: hypotenuse: submit answer

Explanation:

Step1: Find horizontal distance (Leg 1)

The x - coordinates of the points $(-3,-7)$ and $(-7,-1)$ are $-3$ and $-7$. The horizontal distance (difference in x - coordinates) is $|-3-(-7)|=|-3 + 7|=4$.

Step2: Find vertical distance (Leg 2)

The y - coordinates of the points $(-3,-7)$ and $(-7,-1)$ are $-7$ and $-1$. The vertical distance (difference in y - coordinates) is $|-7-(-1)|=|-7 + 1| = 6$.

Step3: Find hypotenuse (distance between points)

Using the Pythagorean theorem, the distance $d$ between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Here, $x_1=-3,y_1=-7,x_2=-7,y_2=-1$. So $d=\sqrt{(-7+3)^2+(-1 + 7)^2}=\sqrt{(-4)^2+(6)^2}=\sqrt{16 + 36}=\sqrt{52}=2\sqrt{13}$.

Answer:

Leg 1: 4, Leg 2: 6, Hypotenuse: $2\sqrt{13}$