Question

the average temperatures for two of the world’s hottest places are given. determine which location has the warmer average temperature and by how many degrees fahrenheit.

location a: 85.3°f and location b: 29.2°c

the location with the warmer average temperature is ▼ which is warmer by about □°f.
(round to the nearest tenth of a degree as needed.)

Explanation:

Step1: Convert Celsius to Fahrenheit

The formula to convert Celsius to Fahrenheit is $F = \frac{9}{5}C + 32$. For Location B, $C = 29.2$.
So, $F=\frac{9}{5}\times29.2 + 32$.
First, calculate $\frac{9}{5}\times29.2 = 1.8\times29.2 = 52.56$.
Then, $52.56 + 32 = 84.56^{\circ}\text{F}$.

Step2: Compare temperatures

Location A: $85.3^{\circ}\text{F}$, Location B: $84.56^{\circ}\text{F}$.
Since $85.3>84.56$, Location A is warmer.

Step3: Find the difference

Subtract the temperature of Location B from Location A: $85.3 - 84.56 = 0.74^{\circ}\text{F}$, round to the nearest tenth is $0.7^{\circ}\text{F}$.

Answer:

The location with the warmer average temperature is Location A, which is warmer by about $0.7^{\circ}\text{F}$.