Question

a car at a red light is initially at rest. when the light turns green the car has an acceleration of 0.6 m/s². after the car has been accelerating for 4.4 seconds, what is its displacement?

Explanation:

Step1: Identify the kinematic - equation

The car starts from rest ($v_0 = 0$), and we use the equation $x=v_0t+\frac{1}{2}at^{2}$.

Step2: Substitute the values

Given $v_0 = 0$, $a = 0.6\ m/s^{2}$, and $t = 4.4\ s$. Substituting into the equation $x=v_0t+\frac{1}{2}at^{2}$, we get $x = 0\times t+\frac{1}{2}\times0.6\times(4.4)^{2}$.

Step3: Calculate the displacement

$x=\frac{1}{2}\times0.6\times4.4^{2}=0.3\times19.36 = 5.808\ m$.

Answer:

$5.808\ m$