Question

an exposure is made using 100 milliamperes (ma) and 0.05 seconds (s). how will the patient dose change if the exposure is repeated using 200 ma and 0.025 s?
○ patient dose increases
○ patient dose decreases
○ patient dose remains the same

Explanation:

Step1: Recall the formula for dose (related to mA and time)

Dose is proportional to the product of mA and time (mA·s).

Step2: Calculate initial mA·s

Initial: \( 100 \, \text{mA} \times 0.05 \, \text{s} = 5 \, \text{mA·s} \)

Step3: Calculate new mA·s

New: \( 200 \, \text{mA} \times 0.025 \, \text{s} = 5 \, \text{mA·s} \)

Step4: Compare the two products

Since both products are equal, the dose (proportional to mA·s) remains the same.

Answer:

Patient dose remains the same