Question

2 fill in the blank 25 points given △jkl with points j(1, -2), k(4, -1), and l(3, -3), graph it, and its reflection in over each line. then fill in the points for △jkl in the space provided. dado △jkl con los puntos j(1, -2), k(4, -1) y l(3, -3), graficarlo, y su reflejo en cada línea. a continuación, rellene los puntos para △jkl en el espacio proporcionado. reflection line (línea de reflexión): x = -1 answer: j ( type your answer... , type your answer... ) k ( type your answer... , type your answer... ) l ( type your answer... , type your answer... )

Explanation:

Step1: Recall reflection over vertical line

The formula for reflecting a point \((x,y)\) over the vertical line \(x = a\) is \((2a - x,y)\). Here, \(a=-1\), so the formula becomes \((2(-1)-x,y)=(-2 - x,y)\).

Step2: Reflect point J(1, -2)

For \(J(1,-2)\), substitute \(x = 1\) into the formula: \(x'=-2 - 1=-3\), \(y'=-2\). So \(J'(-3,-2)\).

Step3: Reflect point K(4, -1)

For \(K(4,-1)\), substitute \(x = 4\) into the formula: \(x'=-2 - 4=-6\), \(y'=-1\). So \(K'(-6,-1)\).

Step4: Reflect point L(3, -3)

For \(L(3,-3)\), substitute \(x = 3\) into the formula: \(x'=-2 - 3=-5\), \(y'=-3\). So \(L'(-5,-3)\).

Answer:

\(J'(-3, -2)\)
\(K'(-6, -1)\)
\(L'(-5, -3)\)