QUESTION IMAGE
Question
find the acceleration of the car in the two regions where the velocity was changing
Response
To find the acceleration in each region, we use the formula for acceleration, \( a = \frac{\Delta v}{\Delta t} \), where \( \Delta v \) is the change in velocity and \( \Delta t \) is the change in time.
For Region \( a_1 \) (Green Region):
Step 1: Identify \( \Delta v \) and \( \Delta t \)
- Initial velocity (\( v_i \)): \( 0 \, \text{m/s} \) (at \( t = 5 \, \text{s} \))
- Final velocity (\( v_f \)): \( 30 \, \text{m/s} \) (at \( t = 10 \, \text{s} \))
- \( \Delta v = v_f - v_i = 30 - 0 = 30 \, \text{m/s} \)
- \( \Delta t = 10 - 5 = 5 \, \text{s} \)
Step 2: Calculate Acceleration
\( a_1 = \frac{\Delta v}{\Delta t} = \frac{30}{5} = 6 \)
For Region \( a_2 \) (Red Region):
Step 1: Identify \( \Delta v \) and \( \Delta t \)
- Initial velocity (\( v_i \)): \( 30 \, \text{m/s} \) (at \( t = 20 \, \text{s} \))
- Final velocity (\( v_f \)): \( 0 \, \text{m/s} \) (at \( t = 30 \, \text{s} \))
- \( \Delta v = v_f - v_i = 0 - 30 = -30 \, \text{m/s} \)
- \( \Delta t = 30 - 20 = 10 \, \text{s} \)
Step 2: Calculate Acceleration
\( a_2 = \frac{\Delta v}{\Delta t} = \frac{-30}{10} = -3 \)
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\( a_1 = 6 \)
\( a_2 = -3 \)