Question

a photon has 8.0×10^(-15) j of energy. plancks constant is 6.63×10^(-34) j·s. what is the frequency of the photon? o 1.21×10^19 hz o 8.3×10^(-20) hz o 1.21×10^(-19) hz o 8.3×10^20 hz

Explanation:

Step1: Recall energy - frequency formula

The energy of a photon is given by $E = hf$, where $E$ is energy, $h$ is Planck's constant, and $f$ is frequency. We need to solve for $f$, so $f=\frac{E}{h}$.

Step2: Substitute given values

Given $E = 8.0\times10^{-15}\text{ J}$ and $h = 6.63\times10^{-34}\text{ J}\cdot\text{s}$. Then $f=\frac{8.0\times 10^{-15}\text{ J}}{6.63\times 10^{-34}\text{ J}\cdot\text{s}}$.

Step3: Calculate the frequency

$f=\frac{8.0}{6.63}\times10^{-15 + 34}\text{ Hz}\approx1.21\times10^{19}\text{ Hz}$.

Answer:

A. $1.21\times 10^{19}\text{ Hz}$