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Question
planes 11. how many points are needed to define a plane? (spcivt check) name the intersection of line \\(\overline{qz}\\) and segment \\(\overline{wu}\\). name the intersection of plane \\(\pi\\) and line \\(\overline{db}\\). name the two opposite rays at point t. what is another name for plane \\(\pi\\)?
1. How many points are needed to define a plane?
Step1: Recall the geometric principle
In geometry, a fundamental principle states that a plane is defined by three non - collinear points. Non - collinear points are points that do not all lie on the same straight line. If we have three non - collinear points, there is exactly one plane that contains all three of them.
Step1: Analyze the diagram
From the given diagram, we can see that line \(\overleftrightarrow{QZ}\) and segment \(\overline{WU}\) intersect at a point. By looking at the labels in the diagram, the point of intersection of line \(\overleftrightarrow{QZ}\) and segment \(\overline{WU}\) is point \(T\).
Step1: Recall the intersection of a plane and a line
The intersection of a plane and a line is either a point (if the line intersects the plane at one point) or the line itself (if the line lies on the plane). From the diagram, line \(\overleftrightarrow{DB}\) lies on plane \(\pi\) (since all the points of the line \(\overleftrightarrow{DB}\) are within the plane \(\pi\) as per the diagram). So the intersection of plane \(\pi\) and line \(\overleftrightarrow{DB}\) is the line \(\overleftrightarrow{DB}\) itself.
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Three non - collinear points are needed to define a plane.