QUESTION IMAGE
Question
9.1 puzzle time
what do you get when you cross a com
with a lifeguard?
write the letter of each answer in the box containing the exercise n
complete the sentence.
- in a(n) right triangle, the square of the length of the
hypotenuse is equal to the sum of the squares of the lengths
of the legs.
- a(n) ______ triple is a set of three positive integers, a, b,
and c, that satisfy the equation ( c^2 = a^2 + b^2 ).
- if the square of the length of the ______ side of a triangle
is equal to the sum of the squares of the lengths of the other
two sides, then the triangle is a right triangle.
- for any ( \triangle abc ), where c is the length of the longest side,
if ( c^2 < a^2 + b^2 ), then ( \triangle abc ) is ______.
- for any ( \triangle abc ), where c is the ______ of the longest side,
if ( c^2 > a^2 + b^2 ), then ( \triangle abc ) is obtuse.
find the value of x.
- ( a = 20, b = 99 ); find x.
- ( a = 60, b = 91 ); find x.
(diagram: right triangle with legs a, b, hypotenuse x)
given the side lengths, determine whether the triangle is (1) ac
- 20, 21, and 29
- 15, 19, and 24
find the value of x.
- ( a = x, b = 45, c = 53 )
- ( a = 9, b = x, c = 41 )
(diagram: right triangle with legs a, b, hypotenuse c)
(answer box with numbers 12, 4, 11, 1, ...)
Let's solve question 6: \(a = 20\), \(b = 99\), find \(x\) (hypotenuse of a right triangle).
Step 1: Recall the Pythagorean theorem
For a right triangle, \(x^{2}=a^{2}+b^{2}\), where \(x\) is the hypotenuse, and \(a\), \(b\) are the legs.
Substitute \(a = 20\) and \(b = 99\) into the formula: \(x^{2}=20^{2}+99^{2}\)
Step 2: Calculate the squares
\(20^{2}=400\), \(99^{2}=9801\)
So, \(x^{2}=400 + 9801=10201\)
Step 3: Take the square root
\(x=\sqrt{10201}\)
Since \(101\times101 = 10201\), we have \(x = 101\)
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\(x = 101\)