Question

question 14 2 pts a train has an initial velocity of 8 m/s. the train has a constant acceleration of 0.8 m/s². after 8 seconds, how far has the train traveled in meters?

Explanation:

Step1: Identify the kinematic formula

We use $s = v_0t+\frac{1}{2}at^{2}$, where $s$ is displacement, $v_0$ is initial velocity, $a$ is acceleration and $t$ is time.

Step2: Substitute given values

Given $v_0 = 8\ m/s$, $a=0.8\ m/s^{2}$, $t = 8\ s$. So $s=(8\times8)+\frac{1}{2}\times0.8\times8^{2}$.

Step3: Calculate the result

First, $8\times8 = 64$. Second, $\frac{1}{2}\times0.8\times8^{2}=0.4\times64 = 25.6$. Then $s=64 + 25.6=89.6$.

Answer:

89.6