Question

question 1b 1b of 6 match each equation on the left side with its solution on the right side. some answer options on the right will not be used. x(2x + 5)(x - 4)=0 x(2x - 5)(x + 4)=0 x(5x + 2)(x - 4)=0 x(5x - 2)(x + 4)=0 x = -5/2 or x = 4 x = 0, x = -5/2, or x = 4 x = 0, x = -2/5, or x = 4 x = 5/2 or x = -4 x = 0, x = 5/2, or x = -4 x = 0, x = 2/5, or x = -4 clear click and hold an item in one column, then drag it to the matching item in the other column. be sure your cursor is over the target before releasing. the target will highlight or the cursor will change. need help? incorrect. to solve an equation in factored form, set each

Explanation:

Step1: Recall zero - product property

If \(abc = 0\), then \(a=0\) or \(b = 0\) or \(c=0\).

Step2: Solve \(x(2x + 5)(x - 4)=0\)

Set \(x=0\) or \(2x+5 = 0\) (so \(x=-\frac{5}{2}\)) or \(x - 4=0\) (so \(x = 4\)). The solutions are \(x = 0,x=-\frac{5}{2},x = 4\).

Step3: Solve \(x(2x - 5)(x + 4)=0\)

Set \(x=0\) or \(2x-5 = 0\) (so \(x=\frac{5}{2}\)) or \(x + 4=0\) (so \(x=-4\)). The solutions are \(x = 0,x=\frac{5}{2},x=-4\).

Step4: Solve \(x(5x + 2)(x - 4)=0\)

Set \(x=0\) or \(5x+2 = 0\) (so \(x=-\frac{2}{5}\)) or \(x - 4=0\) (so \(x = 4\)). The solutions are \(x = 0,x=-\frac{2}{5},x = 4\).

Step5: Solve \(x(5x - 2)(x + 4)=0\)

Set \(x=0\) or \(5x-2 = 0\) (so \(x=\frac{2}{5}\)) or \(x + 4=0\) (so \(x=-4\)). The solutions are \(x = 0,x=\frac{2}{5},x=-4\).

Answer:

\(x(2x + 5)(x - 4)=0\) matches \(x = 0,x=-\frac{5}{2},x = 4\)
\(x(2x - 5)(x + 4)=0\) matches \(x = 0,x=\frac{5}{2},x=-4\)
\(x(5x + 2)(x - 4)=0\) matches \(x = 0,x=-\frac{2}{5},x = 4\)
\(x(5x - 2)(x + 4)=0\) matches \(x = 0,x=\frac{2}{5},x=-4\)