Question

simplify. express your answer using positive exponents. $\frac{10r^{2}g^{0}h^{-1}}{5r^{-1}g^{-38}h^{-1}}$

Explanation:

Step1: Divide the coefficients

$\frac{10}{5}=2$

Step2: Use the quotient - rule of exponents for $r$

$\frac{r^{2}}{r^{-1}}=r^{2-(-1)}=r^{3}$

Step3: Use the quotient - rule of exponents for $g$

$\frac{g^{0}}{g^{-38}}=g^{0-(-38)}=g^{38}$

Step4: Use the quotient - rule of exponents for $h$

$\frac{h^{-1}}{h^{-1}}=h^{-1-(-1)}=h^{0}=1$

Answer:

$2r^{3}g^{38}$