Question

which expression is equivalent to the following complex fraction?
\frac{1 - \frac{1}{x}}{2}

\frac{x - 1}{2x}

\frac{-1}{2}

\frac{2x - 2}{x}

\frac{2x}{x - 1}

Explanation:

Step1: Simplify the numerator

First, simplify $1-\frac{1}{x}$. Get a common - denominator $x$, so $1-\frac{1}{x}=\frac{x}{x}-\frac{1}{x}=\frac{x - 1}{x}$.

Step2: Rewrite the complex - fraction

The original complex fraction $\frac{1-\frac{1}{x}}{2}$ becomes $\frac{\frac{x - 1}{x}}{2}$.

Step3: Divide by 2

Dividing by 2 is the same as multiplying by $\frac{1}{2}$. So $\frac{\frac{x - 1}{x}}{2}=\frac{x - 1}{x}\times\frac{1}{2}=\frac{x - 1}{2x}$.

Answer:

$\frac{x - 1}{2x}$