16. the induced emf of a transformer is 24.0 v when the output voltage is 240.0 v. what is the ratio of the numbers of turns in the primary coil to the numbers of turns in the secondary?
a. 15:1
b. 1:15
c. 1:10
d. 10:1

17. which of the following properties of a material is temperature dependent?
a. opacity
b. mass
c. density
d. weight

18. the air resistance on a parachutist of mass 102 kg falling vertically downward is 150 n. calculate the acceleration of the parachutist. g = 10 ms⁻²
a. 11.4 ms⁻²
b. 8.5 ms⁻²
c. 4.8 ms⁻²
d. 25.5 ms⁻²

19. a golf ball is kicked with an initial velocity of 20 ms⁻¹ at an angle of 60° to the vertical. calculate the magnitude of the horizontal component of the velocity of the ball. g = 10 ms⁻²
a. 23.1 ms⁻¹
b. 17.3 ms⁻¹
c. 10.0 ms⁻¹
d. 40.0 ms⁻¹

20. two metals, a and b gain the same quantity of heat in warming through a temperature difference of 5 °c. given that the ratio of their specific heat capacities are $\frac{a}{b} = \frac{2}{1}$, the ratio of their masses $\frac{m_a}{m_b}$ will be
a. $\frac{1}{2}$
b. $\frac{1}{3}$
c. $\frac{2}{1}$
d. $\frac{3}{1}$

Question

16. the induced emf of a transformer is 24.0 v when the output voltage is 240.0 v. what is the ratio of the numbers of turns in the primary coil to the numbers of turns in the secondary?
a. 15:1
b. 1:15
c. 1:10
d. 10:1

17. which of the following properties of a material is temperature dependent?
a. opacity
b. mass
c. density
d. weight

18. the air resistance on a parachutist of mass 102 kg falling vertically downward is 150 n. calculate the acceleration of the parachutist. g = 10 ms⁻²
a. 11.4 ms⁻²
b. 8.5 ms⁻²
c. 4.8 ms⁻²
d. 25.5 ms⁻²

19. a golf ball is kicked with an initial velocity of 20 ms⁻¹ at an angle of 60° to the vertical. calculate the magnitude of the horizontal component of the velocity of the ball. g = 10 ms⁻²
a. 23.1 ms⁻¹
b. 17.3 ms⁻¹
c. 10.0 ms⁻¹
d. 40.0 ms⁻¹

20. two metals, a and b gain the same quantity of heat in warming through a temperature difference of 5 °c. given that the ratio of their specific heat capacities are $\frac{a}{b} = \frac{2}{1}$, the ratio of their masses $\frac{m_a}{m_b}$ will be
a. $\frac{1}{2}$
b. $\frac{1}{3}$
c. $\frac{2}{1}$
d. $\frac{3}{1}$

Accepted Answer

### Question 16
# Explanation:
## Step1: Recall transformer voltage - turn ratio formula
The formula for the voltage - turn ratio of a transformer is $\frac{V_p}{V_s}=\frac{N_p}{N_s}$, where $V_p$ is the primary voltage (induced emf), $V_s$ is the secondary voltage (output voltage), $N_p$ is the number of turns in the primary coil, and $N_s$ is the number of turns in the secondary coil.
Given $V_p = 24.0\ V$ and $V_s=240.0\ V$.
## Step2: Calculate the ratio $\frac{N_p}{N_s}$
Substitute the given values into the formula: $\frac{N_p}{N_s}=\frac{V_p}{V_s}=\frac{24.0}{240.0}=\frac{1}{10}$

# Answer: C. 1: 10

### Question 17
# Brief Explanations:
- Option A: Opacity is a property related to the ability of a material to block light, and it is not significantly dependent on temperature.
- Option B: Mass is the amount of matter in a substance and is independent of temperature.
- Option C: Density is given by $
ho=\frac{m}{V}$. Volume $V$ of a material generally changes with temperature (due to thermal expansion or contraction), while mass $m$ remains constant. So density is temperature - dependent.
- Option D: Weight is the force due to gravity ($W = mg$) and is independent of temperature (assuming $g$ is constant and mass $m$ is constant).

# Answer: C. Density

### Question 18
# Explanation:
## Step1: Identify the forces acting on the parachutist
The parachutist has a weight $W=mg$ acting downward and air resistance $F_r = 150\ N$ acting upward. The net force $F_{net}=mg - F_r$.
Given $m = 102\ kg$ and $g = 10\ m/s^2$, so $W=mg=102	imes10 = 1020\ N$.
## Step2: Calculate the net force
$F_{net}=1020 - 150=870\ N$
## Step3: Use Newton's second law $F = ma$ to find acceleration
From $F_{net}=ma$, we can solve for $a$: $a=\frac{F_{net}}{m}=\frac{870}{102}\approx8.5\ m/s^2$

# Answer: B. $8.5\ ms^{-2}$

### Question 19
# Explanation:
## Step1: Analyze the angle with respect to the vertical
The initial velocity is at an angle of $60^{\circ}$ to the vertical. So the angle with respect to the horizontal is $	heta=90^{\circ}- 60^{\circ}=30^{\circ}$? Wait, no. Wait, if the angle is with the vertical, the horizontal component of velocity $v_x$ is given by $v\sin	heta$, where $	heta$ is the angle with the vertical.
Given $v = 20\ m/s$ and $	heta = 60^{\circ}$ (with vertical). So $v_x=v\sin60^{\circ}$
## Step2: Calculate the horizontal component
We know that $\sin60^{\circ}=\frac{\sqrt{3}}{2}\approx0.866$. So $v_x = 20	imes\sin60^{\circ}=20	imes\frac{\sqrt{3}}{2}=10\sqrt{3}\approx17.3\ m/s$

# Answer: B. $17.3\ ms^{-1}$

### Question 20
# Explanation:
## Step1: Recall the heat formula $Q = mc\Delta T$
For metal A: $Q_A=m_A c_A\Delta T_A$
For metal B: $Q_B=m_B c_B\Delta T_B$
Given that $Q_A = Q_B$ and $\Delta T_A=\Delta T_B = 5^{\circ}C$, and $\frac{c_A}{c_B}=\frac{2}{1}$
## Step2: Set up the equation and solve for $\frac{m_A}{m_B}$
Since $Q_A = Q_B$, we have $m_A c_A\Delta T_A=m_B c_B\Delta T_B$. Since $\Delta T_A=\Delta T_B$, they cancel out. So $m_A c_A=m_B c_B$.
Rearranging for $\frac{m_A}{m_B}=\frac{c_B}{c_A}$. Given $\frac{c_A}{c_B}=\frac{2}{1}$, then $\frac{c_B}{c_A}=\frac{1}{2}$. So $\frac{m_A}{m_B}=\frac{1}{2}$

# Answer: A. $\frac{1}{2}$

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QUESTION IMAGE

Question

Explanation:

Question 16

Step1: Recall transformer voltage - turn ratio formula

Step2: Calculate the ratio $\frac{N_p}{N_s}$

Step1: Identify the forces acting on the parachutist

Step2: Calculate the net force

Step3: Use Newton's second law $F = ma$ to find acceleration

Answer:

Question 17