QUESTION IMAGE
Question
- solve for x.
triangle with angle 48°, and sides/angles labeled 11x − 5, 9x − 3
Step1: Recall triangle angle sum
The sum of angles in a triangle is \(180^\circ\). So, \(48 + (11x - 5) + (9x - 3) = 180\).
Step2: Simplify the left side
Combine like terms: \(48 - 5 - 3 + 11x + 9x = 180\) → \(40 + 20x = 180\).
Step3: Solve for x
Subtract 40: \(20x = 180 - 40 = 140\). Divide by 20: \(x = \frac{140}{20} = 7\).
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\(x = 7\)