Question

1. the clay has been placed in the graduated cylinder with water. using the water displacement method, find the volume of the clay. v=__ don’t forget the unit! 7. the mass of the clay is 10 grams. what is the density of the clay? d=__ don’t forget the units!

Explanation:

Question 6:

Step1: Identify initial and final volumes

Initial water volume ($V_{initial}$) is 30 mL (from the first graduated cylinder). Final volume ($V_{final}$) with clay is 35 mL (from the second graduated cylinder).

Step2: Calculate volume of clay

Volume of clay ($V$) = $V_{final} - V_{initial}$ = $35\ \text{mL} - 30\ \text{mL}$ = $5\ \text{mL}$ (or $5\ \text{cm}^3$ since 1 mL = 1 cm³).

Step1: Recall density formula

Density ($D$) is given by the formula $D = \frac{m}{V}$, where $m$ is mass and $V$ is volume.

Step2: Substitute values

Mass ($m$) of clay is 10 grams, volume ($V$) from Question 6 is $5\ \text{cm}^3$. So, $D = \frac{10\ \text{g}}{5\ \text{cm}^3}$.

Step3: Calculate density

$\frac{10}{5} = 2$, so density $D = 2\ \text{g/cm}^3$.

Answer:

$5\ \text{mL}$ (or $5\ \text{cm}^3$)

Question 7: