Question

fill in the blank 25 points given △jkl with points j(1, -2), k(4, -1), and l(3, -3), graph it, and its reflection in over each line. then fill in the points for △jkl in the space provided. dado △jkl con los puntos j(1, -2), k(4, -1) y l(3, -3), graficarlo, y su reflejo en cada línea. a continuación, rellene los puntos para △jkl en el espacio proporcionado. reflection line (linea de reflexion): y = 1 answer: j ( type your answer... , type your answer... ) k ( type your answer... , type your answer... ) l ( type your answer... , type your answer... )

Explanation:

Step1: Recall reflection over horizontal line

To reflect a point \((x, y)\) over the line \(y = k\), the formula is \((x, 2k - y)\). Here, \(k = 1\), so the formula becomes \((x, 2(1)-y)=(x, 2 - y)\).

Step2: Reflect point \(J(1, -2)\)

Using the formula, for \(J(1, -2)\): \(x = 1\), \(y=-2\). So the reflected point \(J'\) is \((1, 2 - (-2))=(1, 4)\).

Step3: Reflect point \(K(4, -1)\)

For \(K(4, -1)\): \(x = 4\), \(y = -1\). The reflected point \(K'\) is \((4, 2 - (-1))=(4, 3)\).

Step4: Reflect point \(L(3, -3)\)

For \(L(3, -3)\): \(x = 3\), \(y = -3\). The reflected point \(L'\) is \((3, 2 - (-3))=(3, 5)\).

Answer:

\(J'(1, 4)\)
\(K'(4, 3)\)
\(L'(3, 5)\)