Question

(a) the perimeter of a rectangular parking lot is 254 m. if the width of the parking lot is 58 m, what is its length? length of the parking lot: □ m

Explanation:

Step1: Recall the perimeter formula for a rectangle

The perimeter \( P \) of a rectangle is given by the formula \( P = 2(l + w) \), where \( l \) is the length and \( w \) is the width. We know \( P = 254 \) m and \( w = 58 \) m, and we need to find \( l \). First, we can divide both sides of the formula by 2 to simplify: \( \frac{P}{2}=l + w \).
Substituting the known values, we get \( \frac{254}{2}=l + 58 \).

Step2: Simplify the left - hand side and solve for \( l \)

Simplify \( \frac{254}{2} \), which equals 127. So the equation becomes \( 127=l + 58 \).
To solve for \( l \), we subtract 58 from both sides of the equation: \( l=127 - 58 \).
Calculating \( 127-58 \), we get \( l = 69 \).

Answer:

69