QUESTION IMAGE
Question
of semester test: florida geometry, semester b
an image of a castle is shown. the measurements given represent the stone part of the castle. the height of the tower on the right is 80 feet. the diameter of this tower is 20 feet. the building attached to the tower has a length of 200 feet, width of 40 feet, and height of 60 feet.
first, determine which shapes best model these two sections of the castle. then, determine the approximate surface area of the stone part of the castle given the provided dimensions.
hint: only the lateral surface area needs to be calculated for the tower. for the building, only calculate the area of three of the faces, which represent the stone parts, and subtract out the area where the building attaches to the tower.
Step1: Identify Shapes
The tower is a cylinder (diameter 20 ft, height 80 ft). The building is a rectangular prism (length 200 ft, width 40 ft, height 60 ft).
Step2: Lateral Surface Area of Cylinder
The formula for the lateral surface area of a cylinder is \( LSA = \pi d h \), where \( d = 20 \) ft and \( h = 80 \) ft.
\( LSA_{\text{cylinder}} = \pi \times 20 \times 80 = 1600\pi \approx 5026.55 \, \text{ft}^2 \) (approx 5027 ft²).
Step3: Surface Area of Building (Three Faces - Subtract Attachment)
- Face 1: Length × Height = \( 200 \times 60 = 12000 \, \text{ft}^2 \)
- Face 2: Width × Height = \( 40 \times 60 = 2400 \, \text{ft}^2 \)
- Face 3: Length × Width = \( 200 \times 40 = 8000 \, \text{ft}^2 \) (but subtract the area where it attaches to the cylinder. The attachment area is the area of the circle? Wait, no—the tower is a cylinder, so the attachment area is the area of the circular face? Wait, no, the building is attached to the tower, so the area to subtract is the area of the circle? Wait, no, the tower's diameter is 20 ft, so radius is 10 ft, but the building's width is 40 ft? Wait, maybe the attachment is a rectangle? Wait, no, the hint says "subtract out the area where the building attaches to the tower". The tower is a cylinder, so the attachment area is the area of the circle? Wait, no, the building is a rectangular prism, so when attached to the cylinder, the overlapping area is the area of the circle? Wait, maybe I misread. Wait, the building has length 200, width 40, height 60. The tower has diameter 20, so radius 10. Wait, maybe the attachment is a rectangle with width equal to the diameter of the tower? Wait, the diameter is 20 ft, so the area to subtract is \( 20 \times 60 \)? No, the height of the building is 60, and the tower's height is 80, but the building's height is 60. Wait, the hint says "only calculate the area of three of the faces, which represent the stone parts, and subtract out the area where the building attaches to the tower". So three faces: let's assume the three faces are two side faces (length×height and width×height) and the top/bottom? Wait, no, the building is attached to the tower, so one of its faces is attached, so we calculate three faces (excluding the attached face) and subtract the overlapping area. Wait, maybe the three faces are: length×height, width×height, and length×width, but subtract the area where it attaches to the tower (which is a rectangle with width equal to the diameter of the tower and height equal to the building's height? Wait, the tower's diameter is 20, building's height is 60, so the attached area is \( 20 \times 60 = 1200 \, \text{ft}^2 \)? No, that doesn't make sense. Wait, maybe the building is attached to the tower such that the overlapping area is the area of the circle? No, the tower is a cylinder, so the base is a circle, but the building is a rectangular prism. Wait, perhaps the correct approach is:
For the building: three faces. Let's say the building has dimensions length \( l = 200 \), width \( w = 40 \), height \( h = 60 \). The three faces are:
- Two vertical faces: \( l \times h \) and \( w \times h \)
- One horizontal face: \( l \times w \)
But we need to subtract the area where it attaches to the tower. The tower is a cylinder with diameter 20, so the attached area is a rectangle with width 20 (diameter) and height 60 (building's height)? Wait, no, the tower's height is 80, but the building's height is 60, so the attachment is at the height of the building. Wait, maybe the attached area is the area of the circle? No, the circle's area is…
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The shapes are a cylinder (tower) and a rectangular prism (building). The approximate surface area is \( \boldsymbol{31,427 \, \text{ft}^2} \).