Question

stefano accidentally dropped his sunglasses off the edge of a canyon as he was looking down. the height, h(t), in meters (as it relates to sea level), of the sunglasses after t seconds, is shown in the table. during its descent, the pair of sunglasses passed by a climber in the canyon 6 seconds after stefano dropped them. to the nearest meter, what is difference in elevation between stefano and the climber? height of sunglasses over time

t	h(t)
1	5.1
2	-9.6
3	-34.1
4	-68.4
5	-112.5
6	-166.4
7	-230.1

166 meters
176 meters
230 meters
240 meters

Explanation:

Step1: Identify Stefano's height

At $t = 0$, the height of the sunglasses $h(0)=10$ meters. So Stefano's height relative to sea - level is 10 meters.

Step2: Identify climber's height

At $t = 6$, the height of the sunglasses $h(6)=- 166.4$ meters. So the climber's height relative to sea - level is $-166.4$ meters.

Step3: Calculate the difference in elevation

The difference $\Delta h=10-(-166.4)=10 + 166.4 = 176.4\approx176$ meters.

Answer:

176 meters