Question

which shape has (\frac{1}{2}) shaded?

Explanation:

Step1: Analyze the first shape

Count the total number of squares and the shaded ones. Let's assume the first shape (top - left) has a total of 8 squares (e.g., 2 rows of 4 or other arrangement). Shaded squares: Let's say 5? Wait, no, let's do it properly. Wait, the second shape (top - right) is a rectangle with, say, 8 squares (4 rows of 2? Wait, looking at the top - right shape: it's a column - like with 8 squares? Wait, no, let's count each shape:

Top - left: Let's see, the figure has 8 small squares (e.g., 2 columns of 4? Wait, no, the first figure: left part has 4 squares (2x2) with 2 shaded, right part has 4 squares (2x2) with 4 shaded? Wait, no, maybe better to count total and shaded for each:

1. Top - left: Total squares: Let's count. The figure is made of 8 small squares (e.g., 2 groups of 4). Shaded squares: 5? No, wait, let's look at the second shape (top - right): it's a rectangle with 8 small squares (4 rows, 2 columns). Shaded squares: 4. So total = 8, shaded = 4. So fraction is $\frac{4}{8}=\frac{1}{2}$.

Wait, let's verify each:

• Top - left: Let's count total squares. Suppose the figure has 8 squares (e.g., 2x4). Shaded squares: Let's see, left part: 2 shaded out of 4, right part: 4 shaded out of 4. Total shaded: 2 + 4 = 6. Total: 8. Fraction: $\frac{6}{8}=\frac{3}{4}

eq\frac{1}{2}$.

• Top - right: The figure is a rectangle with 8 small squares (4 rows, 2 columns). Shaded squares: 4 (alternating). So total = 8, shaded = 4. Fraction: $\frac{4}{8}=\frac{1}{2}$.

• Bottom - left: Let's say total squares: 16 (4x4). Shaded squares: Let's count, maybe 8? Wait, no, the figure looks like a 4x4 grid. Shaded squares: Let's see, the blue part: maybe 8? Wait, no, maybe not. Let's check the bottom - right: total squares: 9 (3x3). Shaded squares: 7? No, bottom - right: 3x3 grid, shaded squares: 7? No, wait bottom - right: 3x3, shaded: 7? No, maybe I miscounted. Wait, the top - right shape: it's a vertical rectangle with 8 squares (4 rows, 2 columns). Shaded squares: 4 (since it's checkered: blue, white, blue, white in each column, 2 columns). So 4 shaded, 8 total. So $\frac{4}{8}=\frac{1}{2}$.

Step2: Confirm the fraction for top - right

Total number of squares in top - right shape: Let's count the number of small squares. Looking at the figure, it's a rectangle with 8 small squares (4 rows and 2 columns). Number of shaded squares: 4 (each row has 1 shaded, 4 rows, 2 columns? Wait, no, each column has 4 squares, 2 columns. Shaded squares: 4 (alternating). So total squares $n = 8$, shaded squares $s=4$. The fraction is $\frac{s}{n}=\frac{4}{8}=\frac{1}{2}$.

Other shapes:

• Top - left: Total squares = 8, shaded = 5? No, earlier count was wrong. Wait, top - left: left part is 2x2 (4 squares) with 2 shaded, right part is 2x2 (4 squares) with 4 shaded. Total shaded: 2 + 4 = 6. Fraction: $\frac{6}{8}=\frac{3}{4}$.

• Bottom - left: Let's say 4x4 grid (16 squares). Shaded squares: Let's count, the blue part: maybe 8? No, the figure looks like more. Wait, bottom - left: 4x4, shaded squares: let's see, the blue area: maybe 9? No, not $\frac{1}{2}$.

• Bottom - right: 3x3 grid (9 squares). Shaded squares: 7? No, fraction $\frac{7}{9}

eq\frac{1}{2}$.

So the top - right shape has $\frac{1}{2}$ shaded.

Answer:

The top - right shape (the checkered vertical rectangle) has $\frac{1}{2}$ shaded. (If we consider the options as labeled, for example, if the top - right is option B, then the answer would be B. But since the original problem's figures are not labeled, we describe the shape: the top - right rectangular shape with alternating blue and white squares, having 4 shaded out of 8 total squares.)