QUESTION IMAGE
Question
directions: solve using the square roots method. write all answers in simplest form.
- $x^2 + 4 = 0$
- $-3x^2 = 150$
- $2x^2 + 71 = -163$
- $18 - x^2 = 39$
- $-4x^2 - 3 = 481$
Problem 16: \( x^2 + 4 = 0 \)
Step 1: Isolate \( x^2 \)
Subtract 4 from both sides:
\( x^2 = -4 \)
Step 2: Take square roots
The square root of a negative number involves the imaginary unit \( i \), where \( i^2 = -1 \). Thus:
\( x = \pm \sqrt{-4} = \pm 2i \)
Problem 17: \( -3x^2 = 150 \)
Step 1: Isolate \( x^2 \)
Divide both sides by -3:
\( x^2 = \frac{150}{-3} = -50 \)
Step 2: Take square roots
Using \( i^2 = -1 \):
\( x = \pm \sqrt{-50} = \pm \sqrt{50}i = \pm 5\sqrt{2}i \)
Problem 18: \( 2x^2 + 71 = -163 \)
Step 1: Isolate \( 2x^2 \)
Subtract 71 from both sides:
\( 2x^2 = -163 - 71 = -234 \)
Step 2: Isolate \( x^2 \)
Divide by 2:
\( x^2 = \frac{-234}{2} = -117 \)
Step 3: Take square roots
Using \( i^2 = -1 \):
\( x = \pm \sqrt{-117} = \pm \sqrt{117}i = \pm 3\sqrt{13}i \)
Problem 19: \( 18 - x^2 = 39 \)
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