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Question
- solve the equation. che
\\(\sqrt{m + 3} = \sqrt{2m + 1}\\)
Step1: Square both sides to eliminate roots
$$(\sqrt{m+3})^2 = (\sqrt{2m+1})^2$$
$$m+3 = 2m+1$$
Step2: Isolate variable $m$
$$3 - 1 = 2m - m$$
Step3: Simplify to solve for $m$
$$2 = m$$
Step4: Verify solution in original equation
Left side: $\sqrt{2+3}=\sqrt{5}$
Right side: $\sqrt{2(2)+1}=\sqrt{5}$
Both sides are equal, so solution is valid.
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$m=2$