Question

(\frac{14}{24} - \frac{7}{8} =) (with cancellation marks on numerator/denominator of (\frac{14}{24}))

Explanation:

Step1: Simplify the first fraction

Simplify $\frac{14}{24}$ by dividing numerator and denominator by their greatest common divisor, which is 2. So $\frac{14\div2}{24\div2}=\frac{7}{12}$. Wait, maybe there was a typo or miswriting, looking at the original, maybe it's $\frac{14}{24}$ simplified as $\frac{7}{12}$? Wait no, maybe the first term is $\frac{14}{24}$ and we need to subtract $\frac{7}{8}$. First, find a common denominator. The least common denominator of 24 and 8 is 24.

Step2: Convert $\frac{7}{8}$ to twenty - fourths

To convert $\frac{7}{8}$ to a fraction with denominator 24, multiply numerator and denominator by 3: $\frac{7\times3}{8\times3}=\frac{21}{24}$.

Step3: Subtract the two fractions

Now we have $\frac{14}{24}-\frac{21}{24}$. Wait, that would be negative. Wait, maybe the first fraction was $\frac{14}{24}$ simplified wrong. Wait, maybe the original is $\frac{14}{24}$ and it's a subtraction, but maybe I misread. Wait, no, maybe the first fraction is $\frac{14}{24}$ and we can simplify $\frac{14}{24}$ to $\frac{7}{12}$, and $\frac{7}{8}$ is as is. Wait, no, let's check again. Wait, maybe the first term is $\frac{14}{24}$ and the second is $\frac{7}{8}$. Let's find common denominator 24. $\frac{7}{8}=\frac{21}{24}$. Then $\frac{14}{24}-\frac{21}{24}=\frac{14 - 21}{24}=\frac{-7}{24}$. But that seems odd. Wait, maybe the first fraction was $\frac{14}{24}$ and there was a miscalculation in simplifying. Wait, no, maybe the original problem was $\frac{14}{24}-\frac{7}{8}$, but let's do it correctly.

Wait, maybe the first fraction is $\frac{14}{24}$ and we can reduce $\frac{14}{24}$ to $\frac{7}{12}$, and $\frac{7}{8}$ is $\frac{7}{8}$. The common denominator of 12 and 8 is 24. $\frac{7}{12}=\frac{14}{24}$, $\frac{7}{8}=\frac{21}{24}$. Then $\frac{14}{24}-\frac{21}{24}=-\frac{7}{24}$. But maybe the first fraction was $\frac{14}{24}$ and it's a different operation. Wait, maybe the original was $\frac{14}{24}-\frac{7}{8}$, but let's check again.

Wait, perhaps there was a typo and the first fraction is $\frac{14}{24}$ and the second is $\frac{7}{8}$, but let's proceed with the common denominator method.

1. Find the least common denominator (LCD) of 24 and 8. The prime factors of 24 are $2^3\times3$, and of 8 are $2^3$. So LCD is 24.
2. Rewrite $\frac{7}{8}$ with denominator 24: $\frac{7\times3}{8\times3}=\frac{21}{24}$.
3. Subtract the fractions: $\frac{14}{24}-\frac{21}{24}=\frac{14 - 21}{24}=\frac{-7}{24}$.

But if we consider that maybe the first fraction was $\frac{14}{24}$ and it's a subtraction, but maybe the original problem was $\frac{14}{24}-\frac{7}{8}$, then the result is $-\frac{7}{24}$.

Wait, maybe I misread the first fraction. Let's look at the image again. The first fraction is $\frac{14}{24}$ (with some crossing out, maybe simplifying $\frac{14}{24}$ to $\frac{7}{12}$? Wait, 14 divided by 2 is 7, 24 divided by 2 is 12. Then $\frac{7}{12}-\frac{7}{8}$. Common denominator of 12 and 8 is 24. $\frac{7}{12}=\frac{14}{24}$, $\frac{7}{8}=\frac{21}{24}$. Then $\frac{14}{24}-\frac{21}{24}=-\frac{7}{24}$.

Answer:

$-\frac{7}{24}$