QUESTION IMAGE
Question
ahron j vav date ______ lg: i can classify real numbers into the correct subsets
level 2
identify the sets to which each of the following numbers belongs by marking an \x\ in the appropriate box(es).
| rational | irrational | |
|---|---|---|
| 2) | 2.878787 ... | |
| 3) | √36 | |
| 4) | √23 | |
| 5) | 5/3 | |
| 6) | 8.25371 ... |
- circle the expression that is rational.
a. 6½ − π b. 2.555 ... + √12 c. 2√2 · 3√6 d. √16 − 4⅓
- which terms can be used to classify the expression −7.
a. integer, rational, and real b. irrational and real
c. whole and irrational d. rational and real
place an x in the table to show how many significant digits are in each number.
| number | number of significant digits | ||
|---|---|---|---|
| 1.02 | |||
| 0.0034 | |||
| 321,000 | |||
| 0.4596 |
write in rational exponent form
- ∛x⁸
- ⁵√g³
write in radical form
- a^(7/9)
- w^(2/5)
Problem 1: Classify $\pi$
Step1: Recall rational/irrational def
A rational number can be expressed as $\frac{p}{q}$ ($p,q$ integers, $q
eq0$), irrational cannot. $\pi$ is non - repeating, non - terminating, so irrational.
Step1: Identify number type
$2.878787\cdots$ is a repeating decimal. Repeating decimals can be written as a fraction (e.g., let $x = 2.8787\cdots$, $100x=287.8787\cdots$, $99x = 285$, $x=\frac{285}{99}$), so it's rational.
Step1: Simplify the square root
$\sqrt{36}=6$, and $6=\frac{6}{1}$, which is a rational number (integer, hence rational).
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Irrational: X (Rational: no X)