Question

a car has an initial velocity of 17 m/s. it applies its brakes giving it an acceleration of -1 m/s². how far has the car traveled when it comes to a complete stop?

Explanation:

Step1: Identify the known values

Initial velocity $u = 17$ m/s, final velocity $v=0$ m/s, acceleration $a=- 1$ m/s².

Step2: Use the equation $v^{2}=u^{2}+2as$

We need to solve for $s$. Rearranging the equation $v^{2}=u^{2}+2as$ for $s$ gives $s=\frac{v^{2}-u^{2}}{2a}$.

Step3: Substitute the values

Substitute $v = 0$, $u = 17$ m/s and $a=-1$ m/s² into the formula: $s=\frac{0^{2}-17^{2}}{2\times(-1)}$.
First, calculate $0^{2}-17^{2}=0 - 289=-289$. Then, $2\times(-1)=-2$. So, $s=\frac{-289}{-2}=144.5$ m.

Answer:

144.5 m