Question

complete the paragraph. use the drop - down arrow to choose the correct answer. an aluminum rod is heated from 68°f to 176°f. the rod has a mass of 4.4 lbs and a specific heat capacity of 0.22 btu/lb - °f. the change in the systems heat energy (δq) equals

Explanation:

Step1: Calculate the temperature change

$\Delta T=T_2 - T_1=176 - 68=108^{\circ}F$

Step2: Use the heat - energy formula

The formula for heat energy change is $\Delta Q = mc\Delta T$, where $m$ is the mass, $c$ is the specific heat capacity, and $\Delta T$ is the temperature change.
Substitute $m = 4.4$ lbs, $c=0.22$ BTU/lb - $^{\circ}F$, and $\Delta T = 108^{\circ}F$ into the formula:
$\Delta Q=4.4\times0.22\times108$
$\Delta Q = 4.4\times23.76$
$\Delta Q = 104.544\approx105$ BTU

Answer:

105 BTU