for each value of x, evaluate f(x). |x|f(x)=x^{2}+1| |-2|5| |-1|2| |0| |

$for each value of x, evaluate f(x). |x|f(x)=x^{2}+1| |-2|5| |-1|2| |0| |$

for each value of x, evaluate f(x).

Substitute x = 0 into f(x)=x^{2}+1.
$f(0)=0^{2}+1$

$0^{2}=0$, so $f(0)=0 + 1=1$.

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