Question

inheritance of one trait (such as pod color)
start by placing the alleles of each parent on
the top and left sides of the square. it does
not matter which parent’s alleles are placed
on the top or the side.
fill in the parent’s alleles in the
punnett square below.
legend
g = green pods
g = yellow pods

Explanation:

Step1: Understand Punnett Square Setup

A Punnett square for a single trait (monohybrid cross) requires placing one parent's alleles along the top and the other parent's alleles along the left side. Let's assume typical parent genotypes (e.g., both heterozygous \( Gg \), or one \( GG \) and one \( gg \), etc.). Since the problem is about pod color with \( G \) (green) and \( g \) (yellow), we'll use a common example: let's say the male parent (top) has alleles \( G \) and \( g \), and the female parent (left) has alleles \( G \) and \( g \) (heterozygous parents).

Step2: Place Male Alleles on Top

The male parent's alleles (e.g., \( G \) and \( g \)) go in the top two blue cells (one above each column of the Punnett square).

Step3: Place Female Alleles on Left

The female parent's alleles (e.g., \( G \) and \( g \)) go in the left two red cells (one next to each row of the Punnett square).

For example, if both parents are \( Gg \):

• Top (male): first blue cell \( G \), second blue cell \( g \)
• Left (female): first red cell \( G \), second red cell \( g \)

(Note: The specific alleles depend on parent genotypes, but the process is placing one parent's alleles top, other's left.)

Answer:

Assuming heterozygous parents (\( Gg \times Gg \)):
Top (male) alleles: \( G \), \( g \)
Left (female) alleles: \( G \), \( g \)

(If parent genotypes differ, adjust accordingly, but the key is placing one parent's alleles along top, other along left.)