Question

a line that includes the point (10, -2) has a slope of -3. what is its equation in point - slope form? use the specified point in your equation. write your answer using integers, proper fractions, and improper fractions. simplify all fractions.
y - square = square(x - square)
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Explanation:

Step1: Recall point - slope formula

The point - slope form of a linear equation is $y - y_1=m(x - x_1)$, where $(x_1,y_1)$ is a point on the line and $m$ is the slope of the line.

Step2: Identify values of $x_1,y_1$ and $m$

We are given that the line passes through the point $(10,-2)$, so $x_1 = 10$ and $y_1=-2$. The slope $m=-3$.

Step3: Substitute values into the formula

Substitute $x_1 = 10$, $y_1=-2$ and $m = - 3$ into the point - slope formula $y - y_1=m(x - x_1)$. We get $y-(-2)=-3(x - 10)$, which simplifies to $y + 2=-3(x - 10)$. But we need to write it in the form $y-\square=\square(x - \square)$. So we can rewrite $y + 2$ as $y-(-2)$. So the equation is $y-(-2)=-3(x - 10)$, which means the first box (for $y_1$) is $-2$, the second box (for $m$) is $-3$, and the third box (for $x_1$) is $10$.

Answer:

$y - (-2)=-3(x - 10)$ (or filling in the boxes: the first box is $-2$, the second box is $-3$, the third box is $10$)