Question

5.
$-x + 3 = 6$
6.
$4x - 3 = 13$
7.
$\frac{1}{4}x + 2 = 3$
8.
$12 + 5x - 2x = 27$
9.

10.

Explanation:

Problem 5:

Step1: Subtract 3 from both sides

$-x + 3 - 3 = 6 - 3$
$-x = 3$

Step2: Multiply by -1 to solve for x

$(-1) \times (-x) = 3 \times (-1)$
$x = -3$

Problem 6:

Step1: Add 3 to both sides

$4x - 3 + 3 = 13 + 3$
$4x = 16$

Step2: Divide by 4 to solve for x

$\frac{4x}{4} = \frac{16}{4}$
$x = 4$

Problem 7:

Step1: Subtract 2 from both sides

$\frac{1}{4}x + 2 - 2 = 3 - 2$
$\frac{1}{4}x = 1$

Step2: Multiply by 4 to solve for x

$4 \times \frac{1}{4}x = 1 \times 4$
$x = 4$

Problem 8:

Step1: Combine like terms

$12 + (5x - 2x) = 27$
$12 + 3x = 27$

Step2: Subtract 12 from both sides

$12 + 3x - 12 = 27 - 12$
$3x = 15$

Step3: Divide by 3 to solve for x

$\frac{3x}{3} = \frac{15}{3}$
$x = 5$

Answer:

1. $x = -3$
2. $x = 4$
3. $x = 4$
4. $x = 5$