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Question
question
factor.
$x^2 - 8x + 15$
Step1: Find two numbers
We need two numbers that multiply to \(15\) and add up to \(-8\). The numbers are \(-3\) and \(-5\) since \((-3)\times(-5) = 15\) and \(-3+(-5)=-8\).
Step2: Factor the quadratic
Using the formula \(x^{2}+bx + c=(x + m)(x + n)\) where \(m\) and \(n\) are the two numbers we found, we get:
\(x^{2}-8x + 15=(x - 3)(x - 5)\)
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\((x - 3)(x - 5)\)