Question

question 1 1 pts the work function of a silver surface is 4.73 ev. what would happen if the silver is hit with a photon with 2.5 ev of energy? one electron is released from the metal. a pit forms in the metal due to the impact. nothing, the photon just bounces off the surface. two electrons are released from the metal. question 2 1 pts you shoot a beam of 4.5 ev light at a metal surface and notice that electrons are being released from the metal. what will happen if you then increase the intensity of the 4.5 ev light? the metal will bend and warp. nothing, the energy of the light is the same. more electrons would be released. photons would come off at higher speeds.

Explanation:

For Question 1, in the photoelectric effect, electrons are only emitted from a metal surface if the energy of the incident photon is greater than or equal to the work - function of the metal. Here, the photon energy (2.5 eV) is less than the work - function of silver (4.73 eV), so no electrons are emitted and the photon just bounces off.
For Question 2, in the photoelectric effect, the intensity of light is related to the number of photons. When the energy of the photons is above the work - function (4.5 eV light is causing electron emission), increasing the intensity means more photons are incident on the metal, and thus more electrons will be released.

Answer:

Question 1: Nothing, the photon just bounces off the surface.
Question 2: More electrons would be released.