Question

what is the density of the object? mass of suba diver - 70 kg initial volume - 46 l final volume - 54 l

Explanation:

Step1: Find the volume of the diver

The volume of the diver is the difference between the final volume and the initial volume. So, \( V = \text{Final Volume} - \text{Initial Volume} = 54\space L - 46\space L = 8\space L \). Since \( 1\space L = 1\space dm^3 = 0.001\space m^3 \), but we can also use \( 1\space L = 1000\space cm^3 \) or keep it in liters for density in \( kg/L \).

Step2: Calculate the density

Density \(
ho \) is given by the formula \(
ho=\frac{m}{V} \), where \( m = 70\space kg \) (mass of the diver) and \( V = 8\space L \) (volume of the diver). So, \(
ho=\frac{70\space kg}{8\space L}=8.75\space kg/L \). If we want to convert to \( g/cm^3 \), since \( 1\space kg = 1000\space g \) and \( 1\space L = 1000\space cm^3 \), \(
ho=\frac{70\times1000\space g}{8\times1000\space cm^3}=8.75\space g/cm^3 \) (but usually for such problems, \( kg/L \) or \( g/cm^3 \) can be used, and here \( kg/L \) is straightforward).

Answer:

The density of the object (suba diver) is \( 8.75\space kg/L \) (or \( 8.75\space g/cm^3 \)).