Question

25.1 capacitance
what potential difference is required to charge a 30.0 f capacitor with 150.0 c?

Explanation:

Step1: Recall capacitance formula

The formula for capacitance is $C=\frac{Q}{V}$, where $C$ is capacitance, $Q$ is charge, and $V$ is potential - difference. We need to solve for $V$.

Step2: Rearrange the formula

Rearranging $C = \frac{Q}{V}$ for $V$ gives $V=\frac{Q}{C}$.

Step3: Substitute given values

Given $Q = 150.0\ C$ and $C=30.0\ F$, we substitute into the formula: $V=\frac{150.0\ C}{30.0\ F}$.

Step4: Calculate the result

$V = 5.0\ V$.

Answer:

$5.0\ V$