Question

a cannonball launched with a speed of 46 m/s moves upwards to maximum height. assume the speed changes steadily. determine all unknowns.
s_i = 46 m/s

s = m/s

s_f = 52 m/s

Explanation:

Step1: Analyze the motion at maximum height

At maximum height, the vertical velocity of a projectile (like the cannonball) becomes 0 m/s because it momentarily stops before starting to fall back down. This is a key concept in kinematics for vertical motion under gravity (assuming the motion is vertical or we're considering the vertical component, and since it's launched upwards to max height, the final vertical speed \( s_f \) at max height is 0.

Step2: Confirm the reasoning

When an object is launched upwards and moves to its maximum height, the acceleration due to gravity acts downwards, causing the upward speed to decrease steadily until it reaches 0 at the peak. So the final speed \( s \) (at maximum height) should be 0 m/s.

Answer:

The value of \( s \) (speed at maximum height) is 0 m/s.