Question

1. draw the image of quadrilateral abcd when translated by the directed line segment v. label the image of a as a, the image of b as b, the image of c as c and the image of d as d.

Explanation:

Step1: Identify translation vector

The directed line segment \( v \) shows the translation: count the horizontal and vertical moves. From the start to end of \( v \), it's, say, 3 units right and 0 units up (or as per grid).

Step2: Translate each vertex

• For point \( A \): Move it 3 units right (and same vertical as \( v \)) to get \( A' \).
• For point \( B \): Move \( B \) 3 units right to get \( B' \).
• For point \( C \): Move \( C \) 3 units right to get \( C' \).
• For point \( D \): Move \( D \) 3 units right to get \( D' \).

Step3: Connect the translated vertices

Draw segments \( A'B' \), \( B'C' \), \( C'D' \), \( D'A' \) to form the translated quadrilateral \( A'B'C'D' \).

(Note: Since this is a drawing task, the key is to apply the translation vector to each vertex of \( ABCD \) and connect them. The actual drawing would be on the grid, shifting each point by the same vector as \( v \).)

Answer:

To solve, translate each vertex of \( ABCD \) by the vector \( v \) (e.g., if \( v \) is 3 units right, shift \( A, B, C, D \) 3 units right to get \( A', B', C', D' \), then connect them. The image is the quadrilateral \( A'B'C'D' \) with vertices translated as per \( v \). (Actual drawing requires plotting on the grid with the same translation as \( v \).)